Random sınıfının nextInt() yöntemi, rastgele sayı üretecinin dizisinden sonraki sözde rastgele, eşit şekilde dağıtılmış int değerini döndürür.
Java'da çift
Sözdizimi
public int nextInt()
Parametreler
O
Geri dönüş değeri
nextInt() yöntemi, rastgele sayı üretecinin dizisinden alınan bir sonraki sözde rastgele int değerini döndürür.
örnek 1
import java.util.Random; public class JavaRandomNextIntExample1 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(); System.out.println('Random Integer value : '+val); Integer val1 = random.nextInt(); System.out.println('Random Integer value : '+val1); } } Şimdi Test Edin Çıktı:
Random Integer value : -298063488 Random Integer value : 1400961289
Java Random nextInt() Yöntemi
Random sınıfının nextInt(int n) yöntemi, rastgele sayı üretecinin dizisinden alınan, sıfır (dahil) ile belirtilen değer (hariç) arasında sözde rastgele bir int değeri döndürür.
Sözdizimi
public int nextInt(int n)
Parametreler
N : Döndürülecek rastgele sayının sınırıdır. Olumlu olmalı.
Geri dönüş değeri
nextInt() yöntemi, rastgele sayı üretecinin dizisinden alınan sıfır ile n arasındaki bir sonraki sözde rastgele int değerini döndürür.
Atar
nextInt() yöntemi, eğer n pozitif değilse IllegalArgumentException oluşturur.
Örnek 2
import java.util.Random; public class JavaRandomNextIntExample2 { static int j=1; public static void main(String[] args) { Random random = new Random(); for (int i=1;i<8;i++) { return the next pseudorandom integer value val="random.nextInt(i);" system.out.println(j++ +'. random intvalue : '+val+' '); } < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 1. Random intvalue : 0 2. Random intvalue : 1 3. Random intvalue : 0 4. Random intvalue : 3 5. Random intvalue : 1 6. Random intvalue : 0 7. Random intvalue : 0 </pre> <h2>Example 3</h2> <pre> import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print('Enter number of players.'); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println('Enter name of ' + capacity + ' Players.'); for (int i = 0; i <capacity; i++) { system.out.print(j++ + ' '); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +'. +xyz+' will have '+val+' bonus points.'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;></pre></8;i++)> Örnek 3
import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print('Enter number of players.'); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println('Enter name of ' + capacity + ' Players.'); for (int i = 0; i <capacity; i++) { system.out.print(j++ + \' \'); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +\'. +xyz+\' will have \'+val+\' bonus points.\'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;> Örnek 4
import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } Şimdi Test Edin Çıktı:
Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9)